Solve equations involving cubes and cube roots
Key Notes :
🟢 Solve Equations Involving Cubes and Cube Roots
| Cube of a Number |
- The cube of a number a is a3=a×a×a
- Example: 23=2×2×2=8
| Cube Root of a Number |
- The cube root of a number b is a number x such that x3=b
- Denoted as ∛b=x
- Example: ∛27=3, because 33=27
| Solving Equations Using Cubes |
- General form: x3=k
- To solve: Take cube root on both sides:
x=∛k​
- Example: x3=64
x=∛64=4
| Solving Equations Using Cube Roots |
- General form: ∛x=k
- To solve: Cube both sides:
x=k3
- Example: ∛x=5
x=53=125
| Equations with Constants on Both Sides |
Example: x3+8=27
- Subtract 8 from both sides: x3 = 19
- Take cube root: x = ∛19
| Negative Numbers |
- Cubes of negative numbers are negative:
(−2)3=−8 - Cube roots of negative numbers are negative:
∛−27=−3
| Tips & Tricks |
- Only one real solution exists for cube and cube root equations.
- Always isolate the cube or cube root first before solving.
- Check your answer by cubing or taking cube root to verify.
💡 Quick Reminder:
∛x3 = x and (∛x)3 = x
Learn with an example
Look at this equation:
a3 =125
What is a, the cube root of 125?
a=___
You want to find the cube root of 125, so figure out which number cubed (multiplied by itself, and then multiplied by itself again) equals 125.
The number 5 cubed equals 125.
53 =5.5.5=125
In other words, the equation a3 =125 is true when a=5.
So the cube root of 125 is 5.
Look at this equation:
t3 =8
What is t, the cube root of 8?
t=____
You want to find the cube root of 8, so figure out which number cubed (multiplied by itself, and then multiplied by itself again) equals 8.
The number 2 cubed equals 8.
23 = 2.2.2 =8
In other words, the equation t3 =8 is true when t=2.
So the cube root of 8 is 2.
Look at this equation:
s3 = 27
What is s, the cube root of 27?
s=
You want to find the cube root of 27, so figure out which number cubed (multiplied by itself, and then multiplied by itself again) equals 27.
The number 3 cubed equals 27.
33=3.3.3=27
In other words, the equation 33=27 is true when s=3.
So the cube root of 27 is 3.
Let’s practice!

