Evaluate numerical expressions involving integers
Key Notes :
🔹 What are Integers? |
- Integers are whole numbers and their negatives.
- Examples: …, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5 …
🔹 What is a Numerical Expression? |
- A numerical expression is a combination of numbers and mathematical operations ( +, −, ×, ÷, brackets, exponents).
- Example: 3+(−5)×2
🔹 Order of Operations (BODMAS Rule) |
To evaluate expressions correctly, follow BODMAS:
- B → Brackets (first solve inside brackets)
- O → Orders (powers, squares, roots, etc.)
- D → Division
- M → Multiplication
- A → Addition
- S → Subtraction
🔹 Rules of Integers |
Addition
- (+) + (+) = +
- (−) + (−) = −
- (−) + (+) → subtract and keep the sign of bigger number
Subtraction
- a−b=a+(−b)
Multiplication & Division
- (+) × (+) = +
- (−) × (−) = +
- (+) × (−) = −
- (−) × (+) = −
🔹 Examples |
Example 1:
Evaluate: 5+(−3)
- 👉 5−3=2
Example 2:
Evaluate: (−6)−(−8)
- 👉 −6+8=2
Example 3:
Evaluate: (−4)×(−7)
- 👉 +28
Example 4:
Evaluate: 12÷(−3)
- 👉 −4
Example 5:
Evaluate: [3+(−2)]×(−4)
- 👉 Inside bracket: 3−2=1
- 👉 Multiply: 1×(−4)=−4
Example 6:
Evaluate: (−2)2+(−3)3
- 👉 (−2)2=4
- 👉 (−3)3=−27
- 👉 4+(−27)=−23
🔹 Key Points to Remember |
- Always apply BODMAS when more than one operation is involved.
- Be careful with signs while adding, subtracting, multiplying, and dividing.
- Use brackets to simplify step by step.
- Negative × Negative = Positive; Positive × Negative = Negative.
✅ Practice Questions for Students |
- Evaluate: (−5)+(−8)+12
- Evaluate: 15−(−9)
- Evaluate: (−7)×(−6)÷(−2)
- Evaluate: [10−(−5)]×(−3)
- Evaluate: (−4)3+(2)2
Learn with Example
➡️ Example 1 :
➡️ Evaluate the expression.
2+4÷2
First, identify the operations in the expression.
2+4÷2 This expression has addition and division.
The order of operations says to divide before adding.
2+4÷2=2+2
Now, add 2+2=4.
The value of the expression is 4.
➡️ Example 2 :
Evaluate the expression for x = 5, y = 8 and z = 6.
(y2 + z) ÷ x
Solution :
= (y2 + x) ÷ x
Substitute x = 5, y = 8 and z = 6.
= (82 + 6) ÷ 5
= (64 + 6) ÷ 5
= 70 ÷ 5
= 14
➡️ Example 3 :
Evaluate the expression for p = 6, q = 5 and r = 4.
(PQ – 28)2 ÷ r
Solution :
(PQ – 28)2 ÷ r
Substitute P = 6, Q = 5 and r = 4.
= [(6)(5) – 28]2 ÷ 4
= (30 – 28)2 ÷ 4
= 22 ÷ 4
= 4 ÷ 4
= 1
Let’s practice!🖊️